Answer the attached image.
Answer (1)
Alright, so we’re given two forces: F₁ is 12 N at 22° East of North, and F₂ is 9 N at 15° North of East. To solve for the resultant, we need to break each force into its horizontal (x) and vertical (y) components first. For F₁, since it’s 22° East of North, its x-component is 12 × sin(22°) and its y-component is 12 × cos(22°). For F₂, which is 15° North of East, the x-component is 9 × cos(15°) and the y-component is 9 × sin(15°).Once we get those values, we add the x-components together and the y-components together to get the total x and y of the resultant. Then we use the Pythagorean theorem to find the magnitude of the resultant: √(Rx² + Ry²). For the direction, we use tan⁻¹(Ry/Rx) to get the angle of the resultant from the horizontal.After that, we draw the resultant vector starting from the origin, showing its direction and magnitude. The equilibrant is just the same magnitude as the resultant but in the exact opposite direction, so we draw that going the other way.Don’t forget to round your final answer to two decimal places and box it, just like the instructions say[tex].[/tex]
