The mass of H₂O produced when 209 g of methanol (CH₃OH) are used up can be calculated using stoichiometry and the given balanced equation: 2 CH₃OH + 3 O₂ → 2 CO₂ + 4 H₂O

Question

The mass of H₂O produced when 209 g of methanol (CH₃OH) are used up can be calculated using stoichiometry and the given balanced equation: 2 CH₃OH + 3 O₂ → 2 CO₂ + 4 H₂O​

aeshanicolet · Answer

The answer is = 235 g H2O. Answer:Methanol burns in air to form carbon dioxide and water: 2 CH3OH + 3 O2 ---> 2 CO2 + 4 H2O If 209 g of CH3OH are used up, what mass of H2O is produced? The answer is = 235 g H2O.

Answered by aeshanicolet | 2025-08-26

The mass of H₂O produced when 209 g of methanol (CH₃OH) are used up can be calculated using stoichiometry and the given balanced equation: 2 CH₃OH + 3 O₂ → 2 CO₂ + 4 H₂O​

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The mass of H₂O produced when 209 g of methanol (CH₃OH) are used up can be calculated using stoichiometry and the given balanced equation: 2 CH₃OH + 3 O₂ → 2 CO₂ + 4 H₂O

[Sagot para sa’yo] example of elements and compound and thier reason