Give me a question about this Formula a & Fnet when M=constant step by step without short cut ​

Question: A sled has mass twelve kilograms. A net horizontal force of thirty newtons acts on it. Mass is constant.a) Find the acceleration a.b) If later the sled’s acceleration is measured as five point zero meters per second squared, what is the net force?Solution part a — find acceleration:1. Formula in words: F net equals mass times acceleration.2. Solve for acceleration in words: acceleration equals F net divided by mass.3. Substitute the numbers: acceleration equals thirty newtons divided by twelve kilograms.4. Do the division step by step: twelve goes into thirty two times (because 12 times 2 is 24). Remainder is 6. Write thirty point zero and bring down zero to make sixty. Twelve goes into sixty five times (because 12 times 5 is 60). Remainder zero. So the result is 2 point 5.5. Add units: acceleration equals 2 point 5 meters per second squared.Answer part a: acceleration = 2.5 meters per second squared.Solution part b — find net force when acceleration is 5.0 m/s squared:1. Use the same formula in words: F net equals mass times acceleration.2. Substitute the numbers: F net equals twelve kilograms times five point zero meters per second squared.3. Multiply step by step: 12 times 5 equals 60.4. Add units: net force equals 60 newtons.Answer part b: net force = 60 newtons.have a nice day, kindly brainliest ;⁠)

Answered by miraekiru | 2025-08-25

Here is a step-by-step problem for Newton's second law, F_net = ma, where the mass of the object remains constant:Problem:A 2 kg block rests on a frictionless horizontal surface. A single force of 12 N is applied to the block. What is the net force acting on the block?What is the acceleration of the block?How long will it take the block to travel 30 meters from its starting position?Solution:1. Identify the given information:Mass of the block (m) = 2 kgApplied force (F_applied) = 12 N Surface is frictionless, meaning no friction force is acting against the motion. The block starts from rest (initial velocity, v₀ = 0 m/s).Distance to travel (Δx) = 30 m. 2. Calculate the net force (F_net):Since the surface is frictionless and the applied force is the only force acting in the horizontal direction, the net force is equal to the applied force. F_net = F_appliedF_net = 12 N3. Calculate the acceleration (a):Use Newton's Second Law of Motion: F_net = ma. Rearrange the formula to solve for acceleration: a = F_net / m. Substitute the values: a = 12 N / 2 kg. a = 6 m/s²4. Calculate the time (t) to travel 30 meters:Since the acceleration is constant, we can use a kinematic equation for displacement: Δx = v₀t + (1/2)at². Since the block starts from rest, v₀ = 0, so the equation simplifies to: Δx = (1/2)at². Rearrange to solve for t:2Δx = at²t² = 2Δx / at = √(2Δx / a) Substitute the values: t = √(2 * 30 m / 6 m/s²). t = √(60 m / 6 m/s²). t = √(10 s²). t ≈ 3.16 seconds.

Answered by lakshmi12102008 | 2025-08-25