Please help asap hehe with solutions
Answer (1)
Given:Force (F) = 50 NExtension (x₁) = 0.05 mNew extension (x₂) = 0.08 mAsk:a. Find the spring constant (k).b. Find the work (W) needed to stretch the spring to 0.08 m.Formula:Hooke’s Law: F = kxSpring constant: k = F / xWork done: W = 1/2 kx²Solution:a. k = F / xk = 50 N / 0.05 mk = 1000 N/mb. W = 1/2 kx²W = 1/2 (1000 N/m)(0.08 m)²W = 0.5 × 1000 × 0.0064W = 3.2 JAnswer:a. Spring constant = 1000 N/mb. Work needed = 3.2 Jhave a nice day, kindly brainliest ;)
