Answer:Problem 1: Pea Plant Seed Shape Scenario: In pea plants, round seeds (R) are dominant over wrinkled seeds (r). Cross a homozygous round-seed plant with a homozygous wrinkled-seed plant. Solution:Parental Cross: RR (round) × rr (wrinkled) F1 Generation: All offspring are Rr (round seeds). F1 Self-Cross: Rr × Rr Gametes: R, r (from each parent) Punnett Square: | R | r --|---|--- R | RR| Rr --|---|--- r | Rr| rr F2 Results: Genotypic Ratio: 1 RR : 2 Rr : 1 rrPhenotypic Ratio: 3 round : 1 wrinkledProblem 2: Guinea Pig Coat Color Scenario: Black coat (B) is dominant over white coat (b) in guinea pigs. Cross a heterozygous black guinea pig with a white guinea pig. Solution:Parental Cross: Bb (black) × bb (white) Gametes: B, b (from Bb); b, b (from bb) Punnett Square: | B | b --|---|--- b | Bb| bb --|---|--- b | Bb| bb Offspring Results:Genotypic Ratio: 1 Bb : 1 bbPhenotypic Ratio: 1 black : 1 whiteProblem 3: Human Tongue Rolling Scenario: Tongue rolling (T) is dominant over non-rolling (t). Cross two heterozygous parents. Solution:Parental Cross: Tt (roller) × Tt (roller) Gametes: T, t (from each parent) Punnett Square: | T | t --|---|--- T | TT| Tt --|---|--- t | Tt| tt Offspring Results: Genotypic Ratio: 1 TT : 2 Tt : 1 ttPhenotypic Ratio: 3 rollers : 1 non-roller Key:Homozygous: Identical alleles (e.g., RR, rr). Heterozygous: Different alleles (e.g., Rr, Bb). Phenotype: Observable trait (e.g., round/wrinkled). Genotype: Genetic makeup (e.g., RR, Rr, rr).