what is the value of k in the equation 2(x-7)²=54?
Answer (2)
x = 3√3 + 7We're asked to solve the equation[tex]\sf 2(x-7)^2=54[/tex]Step 1: Divide both sides by 2.[tex]\sf (x-7)^2=27[/tex]Step 2: Take the square root of both sides.[tex]\sf \sqrt{(x-7)^2}=\sqrt{27}[/tex]Step 3: Simplify.[tex]\sf x-7=\sqrt{27}[/tex]Step 4: Simplify the square root.[tex]\sf x-7=3\sqrt{3}[/tex]Step 5: Add 7 to both sides.[tex]\sf x=3\sqrt{3}+7[/tex]
Answer:Let's assume you're asking to solve for x, since there's no "k" in the equation 2(x-7)^2 = 54. 1. Divide both sides by 2:(x-7)^2 = 272. Take the square root of both sides:x-7 = \pm\sqrt{27}3. Simplify the square root:x-7 = \pm 3\sqrt{3}4. Isolate x by adding 7 to both sides:x = 7 \pm 3\sqrt{3} Thus, the values of x are 7 + 3\sqrt{3} and 7 - 3\sqrt{3}.
