Honeylyn is 3 years older than Princess. Princess is 4 years less than twice lovelyn's age. How old are the three girls if their ages add up to 35 ? using a polyas problem solving
Answer (1)
Step-by-step explanation:Step 1: Understand the ProblemHoneylyn (H) is 3 years older than Princess (P): H = P + 3Princess is 4 years less than twice Lovelyn’s (L) age: P = 2L - 4Sum of their ages: H + P + L = 35Step 2: Devise a PlanSubstitute H and P in terms of L into the sum equation.Solve for L, then find P and H.Step 3: Carry Out the PlanH + P + L = (P + 3) + P + L = 35(2L - 4 + 3) + (2L - 4) + L = 35(2L - 1) + (2L - 4) + L = 355L - 5 = 355L = 40L = 8P = 2L - 4 = 2(8) - 4 = 12H = P + 3 = 12 + 3 = 15Step 4: Look Back / CheckH + P + L = 15 + 12 + 8 = 35 ✅Answer:Lovelyn = 8 yearsPrincess = 12 yearsHoneylyn = 15 years
