Answer:Problem:9 \times (4 + 8) \div 6 - \_ \times \_ \div 6 = Let's make the result zero. Solution: Calculate the first part: 9 \times (4 + 8) \div 6 = 18. To make the result zero, we need 9 \times x \div 6 = 18. Find x: 9x \div 6 = 18 \implies x = 12. Therefore, the equation is:9 \times (4 + 8) \div 6 - 9 \times 12 \div 6 = 0