Answer:✨ Situation:A ball is thrown upward from the ground. The height ℎh (in meters) of the ball after t seconds is modeled by:ℎ()=−2+4h(t)=−t2+4tThis is a quadratic equation that shows the ball goes up, reaches a maximum height, then comes down. Equation:ℎ()=−2+4h(t)=−t2+4t Table of Values:t (seconds) 0 1 2 3 4ℎ()h(t) (meters) 0 3 4 3 0 Important Features:Vertex (highest point): At =2, ℎ=4t=2,h=4. → Vertex = (2, 4)Domain (time): 0≤≤40≤t≤4Range (height): 0≤ℎ≤40≤h≤4y-intercept: (0, 0)x-intercepts: (0, 0) and (4, 0)Line of symmetry: =2t=2Opening: Downward (since coefficient of 2t2 is negative) Graph (parabola shape):The parabola starts at (0,0)(0,0), rises to the vertex (2,4)(2,4), then goes down to (4,0)(4,0).