Number of N Atoms in 92.6 g of NH4N02
Answer (1)
Problem: Find the number of nitrogen atoms in 92.6 g of NH4NO2Step 1: Find the molar mass of NH4NO2N = 14 × 2 = 28 g/molH = 1 × 4 = 4 g/molO = 16 × 2 = 32 g/molMolar mass = 28 + 4 + 32 = 64 g/molStep 2: Calculate the number of molesmoles = given mass ÷ molar massmoles = 92.6 ÷ 64moles ≈ 1.447 molStep 3: Find the number of moleculesmolecules = moles × Avogadro’s numbermolecules = 1.447 × 6.022 × 10^23molecules ≈ 8.71 × 10^23 moleculesStep 4: Count the nitrogen atomsEach NH4NO2 molecule has 2 nitrogen atoms.N atoms = molecules × 2N atoms = 8.71 × 10^23 × 2N atoms ≈ 1.74 × 10^24 atoms of nitrogen
