Calculate the mass of liquid water at 100 Celsius that can be totally converted to steam by 3000 joules if the molar enthalpy for vaporization is 40.67 kj/mol
Answer (1)
Given:Energy, Q = 3000 JMolar enthalpy of vaporization, ΔHvap = 40.67 kJ/mol = 40,670 J/molTemperature = 100°C (already at boiling point)Step 1: Calculate moles of water that can be vaporizedMoles, n = Q / ΔHvapn = 3000 J / 40,670 J/mol ≈ 0.0737 molStep 2: Convert moles to massMolar mass of water = 18 g/molMass, m = n × molar massm = 0.0737 mol × 18 g/mol ≈ 1.33 gAnswer:Approximately 1.33 grams of water can be converted to steam.
