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In Math / Elementary School | 2025-08-10

Mr. Nabong has to. print certificates for grade 4 for 9 section. the A. M shift has 6 section with the total number of learners of 354 and the P. M shift has 5 sectios with the total number of learners of 268 without the Absences. if he were to estimate the total learners of A. m at P. m. how many certificate he has to print per shifting schedule? askedgiven operationssolve ​

Asked by salazarshanayah

Answer (1)

Mr. Nabong needs to print certificates for Grade 4 students in 9 sections. The morning shift has 6 sections with 354 learners, and the afternoon shift has 5 sections with 264 learners. We need to find out how many certificates he needs to print per shift.Given:Number of sections in A.M shift = 6Total number of learners in A.M shift = 354Number of sections in P.M shift = 5Total number of learners in P.M shift = 264Asked:Number of certificates to print per shift.Operation:To find the number of certificates to print per shift, we simply use the total number of learners in each shift.Solution:Certificates for A.M shift = Total number of learners in A.M shift = 354Certificates for P.M shift = Total number of learners in P.M shift = 264Answer:Mr. Nabong has to print 354 certificates for the A.M shift and 264 certificates for the P.M shift.

Answered by zianna68 | 2025-08-13