1. Salt water solution- A solution is made by dissolving 10 grams of salt in 90 grams of water. What is the percent by mass of salt and the percent by mass of water in the solution2. Sugar in tea-A cup of sweet tea contains 20 grams of sugar and the total mass of the water is 70 grams. Calculate the percent by mass of sugar and the percent by mass of the tea
Answer (1)
In the salt water solution: 10% salt and 90% waterIn the sweet tea: 22.22% sugar and 77.78% water (tea)[tex]\begin{gathered}\begin{gathered}\text{Percent by mass} = \left(\frac{\text{mass ng component}}{\text{total na mass ng solusyon}}\right) \times 100\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]1. Salt water solution:Mass of salt (solute) = 10 gMass of water (solvent) = 90 gTotal mass of solution = 10 g + 90 g = 100 gPercent by mass of salt: [tex]\frac{10}{100} \times 100 = 10%[/tex]Percent by mass of water: [tex]\frac{90}{100} \times 100 = 90[/tex]2. Sugar in tea:Mass of sugar (solute) = 20 gMass of water (solvent) = 70 gTotal mass of tea solution = 20 g + 70 g = 90 gPercent by mass of sugar: [tex]\frac{20}{90} \times 100 \approx 22.22%[/tex]Percent by mass of water (or tea without sugar): [tex]\frac{70}{90} \times 100 \approx 77.78%[/tex]
