2x2-3x-14>0 using quadratic inequalities
Answer (1)
Answer:x > (7/2) andx > -2Step-by-step explanation:Let's assume that "2x2-3x-14>0" is meant to read "2x^2 -3x -14 > 0"2x^2 -3x -14 > 0Let's look for two numbers whose product is 2*(−14) = −28 and whose sum is −3.Those numbers could be −7 and 4.Rewrite -3x as "-7x + 4x"2x^2 −7x + 4x −14 > 0Group terms:(2x^2 −7x) + (4x −14) > 0Factor each group: x(2x −7) + 2(2x −7) > 0Note that (2x-7) appears in both terms, Factor it out:(2x −7) (x +2) > 0This gives us: (2x −7) > 0, or x > (7/2) and (x +2) > 0, or x > -2
