Coat color and tail lenght in dogsIn dogs, coat color and tail lenght are determined by two separate genes Coat Color (B) B - Black coat b - Brown coatTail lenght (T) T - long tailst - short tailsparent 1- Heterozygous for both coat color (Bb) and tail lenght (Tt) exhibiting black coat color and long tailparent 2- Honozygous reccesive for both traits ( bb, tt) displaying brown coat color and short tail.
Answer (1)
In dogs, coat color and tail length are determined by two separate genes. For coat color, the B allele (black) is dominant over the b allele (brown). For tail length, the T allele (long) is dominant over the t allele (short). A heterozygous parent with genotype BbTt (black coat, long tail) will produce four possible gametes: BT, Bt, bT, and bt. A homozygous recessive parent with genotype bbtt (brown coat, short tail) will only produce one type of gamete: bt. When these two parents mate, the offspring will exhibit a 1:1:1:1 ratio of black coat/long tail, black coat/short tail, brown coat/long tail, and brown coat/short tail. Here's a more detailed breakdown:Parent 1 (BbTt): Genotype: Heterozygous for both coat color (Bb) and tail length (Tt).Phenotype: Black coat and long tail.Gametes: BT, Bt, bT, bt.Parent 2 (bbtt): Genotype: Homozygous recessive for both coat color and tail length (bbtt).Phenotype: Brown coat and short tail.Gametes: bt.Punnett Square:A Punnett square can be used to predict the offspring's genotypes. Since parent 2 can only produce one type of gamete (bt), it simplifies the analysis. BTBtbTbtbtBbTtBbttbbTtbbttOffspring Phenotypes:BbTt: Black coat, long tail.Bbtt: Black coat, short tail.bbTt: Brown coat, long tail.bbtt: Brown coat, short tail. Phenotypic Ratio:The offspring will have a phenotypic ratio of 1:1:1:1 for the following traits: 1 Black coat, long tail1 Black coat, short tail1 Brown coat, long tail1 Brown coat, short tail
