How to solve this? Y=ax²+bx+c -› y=a(x-h)²+k
Y=3x²+ -4+1 -› y=a (x-1.5)² + -3

Answer:To solve the quadratic equation and rewrite it in vertex form, follow these steps:1. Start with the given quadratic equation: y = 3x² - 4x + 1.2. To complete the square, factor out the coefficient of x² from the first two terms:   y = 3(x² - (4/3)x) + 1.3. Complete the square inside the parentheses:   - Take half of the coefficient of x (which is -4/3), resulting in -2/3.   - Square this value: (-2/3)² = 4/9.   - Add and subtract this inside the parentheses to maintain equality:     y = 3[x² - (4/3)x + 4/9 - 4/9] + 1.4. Simplify by grouping the perfect square trinomial:   y = 3[(x - 2/3)² - 4/9] + 1.5. Distribute the 3:   y = 3(x - 2/3)² - 4/3 + 1.6. Combine constants:   y = 3(x - 2/3)² - (4/3) + (3/3) = 3(x - 2/3)² - 1/3.Thus, the quadratic in vertex form is y = 3(x - 2/3)² - 1/3, where the vertex is at (2/3, -1/3).Step-by-step explanation:

Answered by rosezysoledad | 2025-08-06