X²+5x-14=0 quadratic folmula
Answer (1)
[tex]\large{\bold{SOLUTION}}[/tex]The quadratic formula is[tex]\blue{\Large\boxed{\sf{x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}}}[/tex]Plug in the values:A = 1, B = 5, C = 14[tex]\sf{x = \dfrac{-5 \pm \sqrt{5^2 - 4(1)(14)}}{2(1)}}[/tex][tex]\sf{x = \dfrac{ - 5 \pm \sqrt{25 + 56}}{2}}[/tex][tex]\sf{x = \dfrac{ - 5 \pm \sqrt{81}}{2}}[/tex][tex]\sf{x_{1} = \dfrac{ - 5 + 9}{2}} = \green{\boxed2} \\ \sf{x_{2} = \dfrac{ - 5 - 9}{2}} = \green{\boxed{ \green{{-7}}}}[/tex]
