5. What is the main cause of extinction in plan II. Work on the following problems: 1. Suppose 60 ants live in a 4 sq. m. plot of grass. What would be the population density of the ants? What would the population density be if 100 ants live in an 8 sq. m. plot of grass? 2. If 40 carabaos live in a 1 ½ sq. km. area, what is their population density per sq. km.? 3. How many monkeys would have to live in a 3/4 sq. km. area to have the same population density as the carabao?
Answer (1)
1. Main Cause of Extinction in Plan II:Although "Plan II" is vague and lacks context, a common main cause of extinction in many conservation plans is habitat destruction—when animals or plants lose their natural homes due to farming, logging, mining, or urban development.2. Population Density Problems (Population ÷ Area):a. 60 ants in 4 sq. m.→ 60 ÷ 4 = 15 ants per sq. m.b. 100 ants in 8 sq. m.→ 100 ÷ 8 = 12.5 ants per sq. m.c. 40 carabaos in 1.5 sq. km.→ 40 ÷ 1.5 = 26.67 carabaos per sq. km.d. Monkeys in ¾ sq. km. with same density as carabaos (26.67):→ Needed: 26.67 × 0.75 = 20 monkeys
