Sum and product o roots Solve the following equa 1. x(x-3)=10​

In the given equation, the sum of the roots is 3 and the product of the roots is -10To find the sum and product of the roots, we need to follow the formula. First we convert the equation into standard form and to find the sum, the formula is -b/a  To find the product, the formula is c/aFirst, standardize the equation by following the form [tex]ax^2 + bx + c =0[/tex]We can do this by distributing x to (x-3)x(x) = [tex]x^2[/tex]x(-3)= -3x[tex]x^{2} -3x[/tex] = 10Then, we transpose 10 and it'll become -10Therefore, the standard form is [tex]x^{2} -3x-10[/tex]From the standard form, we can conclude that:a=1b=-3c=-10To find the sum, let's substitute it to the formula -b/a[tex]\frac{-b}{a}[/tex][tex]\frac{-(-3)}1}[/tex] [tex]\frac{3}{1}[/tex]  (negative times negative is positive)= 3/1 or 3Therefore, the sum of the roots is 3To find the product, substitute to the formula c/a[tex]\frac{c}{a}[/tex][tex]\frac{-10}{1}[/tex]=-10/1 or -10Therefore, the product of the roots is -10

Answered by keinasour | 2025-07-27