\boxed{x^3 + 2x^2 - 1}---2. (x³ - 7x + 6) ÷ (x + 1)Again, write it in standard form (notice: there’s no term):x^3 + 0x^2 - 7x + 6We divide by , so we can use synthetic division with :Synthetic Division:\begin{array}{r|rrrr}-1 & 1 & 0 & -7 & 6 \\ & & -1 & 1 & 6 \\\hline & 1 & -1 & -6 & \boxed{12}\end{array}So the quotient is:x^2 - x - 6, \text{ remainder } 12