given a geometric sequence 4,8,16 find the 8th term in the sequence? given
Answer (1)
The 8th term in the given geometric sequence is 512We can multiply 4 by the common ratio 7 times to get to the eighth term or we can we follow the formula for geometric sequence [tex]a_n = a_1 \times r^n^-^1[/tex] First, we get the common ratio by dividing [tex]a_2[/tex] by [tex]a_1[/tex][tex]a_2\div\ a_1[/tex][tex]8\div4[/tex]=2Substitute for the given values[tex]a_n = a_1 \times r^n^-^1[/tex] [tex]a_8 = 4 \times2^8^-^1[/tex]Subtract 8 by 1 in the exponent[tex]a_8 = 4 \times2^7[/tex]Solve 2 raised to 7[tex]= 4 \times128[/tex]Multiply 4 by 128[tex]a_8[/tex]=512Therefore, the 8th term in the given sequence is 512
