\boxed{(2a + 3)(a - 5)}---2. Solve:3x² + 11x + 6 = 0Step 1: Multiply the first and last coefficients:Step 2: Find two numbers that multiply to 18 and add to 11: and Step 3: Rewrite the middle term using those numbers:Step 4: Factor by grouping:(3x² + 9x) + (2x + 6) = 0 \\3x(x + 3) + 2(x + 3) = 0Step 5: Factor the common binomial:(3x + 2)(x + 3) = 0