solve the 2x²+8x+6=0

x = -3 and x = -1The point of this activity is to solve the following equation:[tex]\sf 2x^2+8x+6=0[/tex]Step 1: Divide both sides by 2. Make sure you divide each term by 2.[tex]\sf x^2+4x+3=0[/tex]Step 2: Factor.[tex]\sf (x \ \ )(x \ \ )=0[/tex]We need to think of two numbers that meet these conditions:→ When you multiply them, you get 3.→ When you add them, you get 4.These numbers are 3 and 1. Step 3: Put these numbers in the blanks:[tex]\sf (x+3)(x+1)=0[/tex]Step 4: Set both of these equations to zero:[tex]\sf x+3=0 \quad and \quad x+1=0[/tex]Step 5: Solve them.[tex]\sf x=-3 \quad and \quad x=-1[/tex]

Answered by Eloquence | 2025-07-23