Three boys went in the market. Raymond bought ½ kg of squash. Justine bought ¼ kg of petchay. August bought 1 ½ kg of cabbage. How many kilograms greater was the vegetable bought by August than the vegetables bought by the two boys?
Answer (1)
Answer:(3/4) kgStep-by-step explanation:Raymond: 1/2 kg squashJustine: 1/4 kg petchayAugust: 1 1/2 kg cabbageTotal mass of vegetables for Raymond and Justine = (1/2) + (1/4) kg (1/2)(2/2) + (1/4) kg [Multiply the (1/2) by (2/2)[ = 1] to change the denominator to a 4, so that both denominators are the same] (2/4) + (1/4) kg (3/4) kg total for Raymond and Justine Convert August's 1 1/2 kg to a fraction with a denominator of 4: (1 + (1/2)) kg (1*(4/4) + (1/2)*(2/2)) kg (4/4) + (2/4) = (6/4) kg for AugustNow the total for Raymond and Justine and the mass of August's cabbage all have the same denominator, so that the difference can be calculated: August - (Raymond plus Justine) = Difference of the two masses of veggies (6/4) kg - (3/4) kg = (3/4) kg, the mass difference between August and the other two. August's cabbage has (3/4) kg more mass than the total masses of Raymond and Justine's vegetables.
