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In Math / Senior High School | 2025-07-22

(ab ²c) (4a²b³-6a⁴bc²)

Asked by guinethviloria5

Answer (1)

Answer:[tex]4 {a}^{2} {b}^{5} c - 6 {a}^{5} {b}^{3} {c}^{3} [/tex]Step-by-step explanation:[tex](a {b}^{2} c)(4 {a}^{2} {b}^{3} - 6 {a}^{4} b {c}^{2} ) = (a {b}^{2} c)(4 {a}^{2} {b}^{3} ) + (a {b}^{2} c)( - 6 {a}^{4} b {c}^{2} ) = 4 {a}^{2} {b}^{5} c -6 {a}^{5} {b}^{3} {c}^{3} [/tex]

Answered by bramboyon65 | 2025-07-22