A group of hikers consumed 3/5 liters of water per person. If there were 7 hikers, and they had 1 1/2 liters left after the hike, how many liters of water did they start with?
Answer (1)
The hikers started with[tex]$$5 \dfrac{7}{10}$$[/tex] liters of water1. Calculate Total Water ConsumedEach of the 7 hikers drank [tex]$$\dfrac{3}{5}$$[/tex] liters. So, the total water consumed is:[tex]$$7 \times \dfrac{3}{5} = \dfrac{21}{5} \text{ liters}$$[/tex] 2. Convert Remaining WaterThe remaining water, [tex]$$1 \dfrac{1}{2}$$[/tex] liters, is [tex]$$\dfrac{3}{2}$$[/tex] liters in improper fraction form.3. Find Initial Amount of WaterSet up the equation:[tex]$$x - \dfrac{21}{5} = \frac{3}{2} \implies x = \frac{3}{2} + \frac{21}{5}$$[/tex]Solve for x4. Use a common denominator (which is 10) to add:[tex]$$x = \dfrac{15}{10} + \frac{42}{10} = \frac{57}{10}$$[/tex] 5. Convert to Mixed NumberThe initial amount of water is [tex]$$5 \dfrac{7}{10}$$[/tex] liters.
