the rectangle has an are of 90 square meters let's length is 5 meters more than it's width find the dimensions of the rectangle
Answer (1)
Answer:width = 7.31 mlength = 12.31 mStep-by-step explanation:area = width(length)90=w(w+5)we distribute90=w²+5wnow we can transpose and equate to 0w²+5w-90=0we can find the value of w by using the quadratic formula[tex]$$w = \frac{-b \pm \sqrt{b^2 - 4ac}}$$[/tex]______________ 2aa = 1b= 5c=90[tex]$$w = \frac{-5 \pm \sqrt{385}}$$[/tex]___________ 2(1)[tex]$$w = \frac{-5 \pm 19.62}$$[/tex]___________ 214.62/2 =7.3107084... ( we're not gonna include the negative because you can't have a negative value in measurements)we can roud off the width to 7.31width = 7.31 mlength = 7.31+5 = 12.31 m
