A beach ball with a volume of 5000cm³ is pushed under water.what is the magnitude of the buoyant force pushing upwards?
(Density of water =1 g/cm³
Answer (1)
Answer:The magnitude of the buoyant force is equal to the weight of the water displaced by the beach ball. Since the beach ball is fully submerged, the volume of water displaced is equal to the volume of the beach ball (5000 cm³). - Mass of displaced water: Density × Volume = 1 g/cm³ × 5000 cm³ = 5000 g = 5 kg- Weight of displaced water: Mass × g (acceleration due to gravity) ≈ 5 kg × 9.8 m/s² ≈ 49 N Therefore, the magnitude of the buoyant force pushing upwards is approximately 49 N.
