4+20r+25=0. quadratic equations solution and answers
Answer (1)
Answer:-5/2Step-by-step explanation:Do you mean 4r²+20r+25=0? because for something to be considered quadratic, it needs to have a degree of polynomial that's 2.[tex]$$ 4r^2 + 20r + 25 = 0 $$[/tex]we can determine from this given thata = 4b= 20c=25Let's use the quadratic formula[tex]$$ r = \frac{-b \pm \sqrt{b^2 - 4ac}} $$[/tex]-------------------------- 2asubstitute the given values[tex]$$ r = \frac{-20 \pm \sqrt{0}} $$[/tex]-------------------2(4)-20/8=-5/2
