how many terms are there in arithmetic sequence with a common difference of 4 and with the first and last terms 3 and 59 respectively
Answer (1)
Let's use the formula for the nth term of an arithmetic sequence:an = a1 + (n - 1)dwhere:an = last term = 59a1 = first term = 3d = common difference = 4n = number of terms59 = 3 + (n - 1)4Subtract 3 from both sides:56 = (n - 1)4Divide both sides by 4:14 = n - 1Add 1 to both sides:n = 15There are 15 terms in the sequence.
