completing the square of x²-4x-32=0​

Answer:Start sa equation: x² - 4x - 32 = 0Move constant: x² - 4x = 32Take half ng coefficient ng x, which is -4, so half is -2.Square mo siya: (-2)² = 4. Add 4 both sides para balanced:x² - 4x + 4 = 32 + 4Left side becomes perfect square: (x - 2)² = 36Solve for x by taking square root: x - 2 = ±6So, x = 2 ± 6 → x = 8 or x = -4

Answered by okinagatarashimiyeon | 2025-07-14