what is the sum of the first 42 terms of an arithmetic sequence where the first term is 3 and the last term is 167?
Answer (1)
Answer:The sum of an arithmetic series can be found using the formula: Sn = n/2 * (a1 + an) Where: - Sn is the sum of the first n terms- n is the number of terms- a1 is the first term- an is the last term In this case: - n = 42- a1 = 3- an = 167 Plugging these values into the formula: S42 = 42/2 * (3 + 167) = 21 * 170 = 3570 Therefore, the sum of the first 42 terms is \boxed{3570}.
