make a cross between a mother with a blood type AB and the following type A blood
Answer (1)
A cross between a mother with blood type AB (genotype IAIB) and a father with blood type A (genotype IAIA or IAi) can result in children with blood types A or B. Specifically, if the father has the genotype IAIA, all children will have blood type A (genotype IAIA or IAi). If the father has the genotype IAi, there's a 50% chance of children with blood type A (genotype IAIA or IAi) and a 50% chance of children with blood type B (genotype IBi). Here's a breakdown: Mother (AB): IAIBFather (A): IAIA or IAiPossible Genotypes and Phenotypes in offspring:If the father is IAIA:IAIB (from mother) + IAIA (from father) = IAIA (blood type A)IAIB (from mother) + IAIA (from father) = IAi (blood type A)If the father is IAi:IAIB (from mother) + IAi (from father) = IAIA (blood type A)IAIB (from mother) + IAi (from father) = IAi (blood type A)IAIB (from mother) + ii (from father) = IBi (blood type B)Therefore, the possible blood types of their children are A or B.
