first 25 terms of the arithmetic sequence 4,9,14,19,24.….
Answer (1)
Answer:4, 9, 14, 19, 24, 29, 34, 39, 44, 49, 54, 59, 64, 69, 74, 79, 84, 89, 94, 99, 104, 109, 114, 119, 124Step-by-step explanation:9 - 4 = 514 - 9 = 519 - 14 = 524 - 19 = 524 + 5 = 2929 + 5 = 3434 + 5 = 3939 + 5 = 4444 + 5 = 4949 + 5 = 5454 + 5 = 5959 + 5 = 6464 + 5 = 6969 + 5 = 7474 + 5 = 7979 + 5 = 8484 + 5 = 8989 + 5 = 9494 + 5 = 9999 + 5 = 104104 + 5 = 109109 + 5 = 114114 + 5 = 119119 + 5 = 124you can also use this formula[tex]a_{n} \: = \: a_{1} \: + \: (n \: - \: 1 \: )d[/tex]where [tex] a_{n}[/tex] is the nth term[tex] a_{1}[/tex]is the first termn is the term numberd is the common difference between consecutive terms
