find the 53rd term of the arithmetic sequence 10,6,2
Answer (1)
Step 1: Identify the first term (a₁) and the common difference (d)a_1 = 10d = 6 - 10 = -4 Step 2: Use the formula for the nth term of an arithmetic sequence a_n = a_1 + (n - 1)dStep 3: Substitute n = 53 , a_1 = 10 , and d = -4 a_{53} = 10 + (53 - 1)(-4) = 10 + 52 \times (-4) = 10 - 208 = -198Answer:The 53rd term is -198.
