(a) y=2x+1 (b) y = x²-2x+2 (c) x² + y² = 1 (d) y = √x+1 paki solve yan isa isa para saakin
Answer (1)
Answer:(a) Type: Linear functionSolution: This is already solved for . You can find values of for different .Sample values:x y = 2x + 1-2 -3-1 -10 11 32 5This is a straight line with slope 2 and y-intercept 1.---(b) Type: Quadratic functionSolution: Already solved for . We just evaluate.Sample values:x y = -1 50 21 12 23 5This is a parabola opening upwards, and the minimum value is at x = 1, where .---(c) Type: Circle equationSolution: This is the equation of a circle centered at the origin (0, 0) with radius = 1.To find sample points, we use values where the sum of squares = 1.Sample solutions:(1, 0)(-1, 0)(0, 1)(0, -1)This equation is not solved for , but you can rewrite it as:y = \pm \sqrt{1 - x^2}That gives the top and bottom halves of the circle.---(d) Type: Square root functionDomain: (because you can’t take the square root of a negative number in real numbers)Sample values:x y = √(x+1)-1 00 13 28 315 4This is a curve starting at (−1, 0) and going up slowly to the right.
