By Entracing the
Square rost of DE
1- 4x2-6=99

Step-by-step explanation:\[x = \pm \sqrt{26}i\]where \(i\) is the imaginary unit, defined as \(\sqrt{-1}\).*Final Answer*The solutions to the equation are:\[\boxed{x = \pm \sqrt{26}i}\]This indicates that the equation has complex solutions, reflecting the nature of the quadratic equation when it results in a negative under the square root.To solve the equation \(1 - 4x^2 - 6 = 99\), let's follow these steps:*Step 1: Simplify the Equation*First, combine like terms on the left side of the equation:\[1 - 6 - 4x^2 = 99\]\[-5 - 4x^2 = 99\]*Step 2: Isolate the Variable Term*Next, isolate the term with \(x^2\) by adding 5 to both sides of the equation:\[-4x^2 = 99 + 5\]\[-4x^2 = 104\]*Step 3: Solve for \(x^2\)*Now, divide both sides by -4 to solve for \(x^2\):\[x^2 = \frac{104}{-4}\]\[x^2 = -26\]*Step 4: Solve for \(x\)*Since \(x^2 = -26\), and the square of a real number cannot be negative, this equation has no real solutions. However, in the complex number system, we can express the solution as:\[x = \pm \sqrt{-26}\]

Answered by joycristalmhariecatu | 2025-07-06