a4=41 a12= 10s; s8 give me the answer

Answer: 360 broStep-by-step explanation:To find the sum of the first 8 terms (s8) of the arithmetic sequence, we need to find the first term (a1) and the common difference (d).Given:a4 = 41a12 = 105 Step 1: Find the common difference (d)We can use the formula: an = a1 + (n-1)dLet's use the given terms to set up two equations:a4 = a1 + 3d = 41 ... (1)a12 = a1 + 11d = 105 ... (2)Subtracting (1) from (2), we get:8d = 64d = 8 Step 2: Find the first term (a1)Now that we have the common difference (d), we can find the first term (a1) using one of the equations:a1 + 3d = 41a1 + 3(8) = 41a1 + 24 = 41a1 = 17## Step 3: Find the sum of the first 8 terms (s8)The formula for the sum of an arithmetic series is:sn = n/2 [2a1 + (n-1)d]s8 = 8/2 [2(17) + (8-1)8]= 4 [34 + 56]= 4 [90]= 360

Answered by esculturajoenard0 | 2025-07-03