Answer:Here are the solutions to the perimeter problems you provided: 1. Find the perimeter of the given figure You mentioned dimensions: 14 m, 8 m, 8 m, 8 m, 8 m, and 22 m, but without a figure, I interpret these as side lengths of a polygon.Add all sides:Perimeter = 14 + 8 + 8 + 8 + 8 + 22 = 68 m 2. Rectangle with length 17 m and width 13 m Perimeter P = 2 \times (length + width) = 2 \times (17 + 13) = 2 \times 30 = 60 \text{ m} 3. Perimeter of a square with side 35 cm Perimeter P = 4 \times side = 4 \times 35 = 140 \text{ cm} 4. Perimeter of an equilateral triangle with side 9 m Perimeter P = 3 \times side = 3 \times 9 = 27 \text{ m} 5. Rectangle with width 23 cm and length three times its width Length = 3 \times 23 = 69 \text{ cm}Perimeter P = 2 \times (length + width) = 2 \times (69 + 23) = 2 \times 92 = 184 \text{ cm} 6. Square M has the same perimeter as rectangle N (length 11 m, width 9 m) Perimeter of rectangle N: 2 \times (11 + 9) = 2 \times 20 = 40 \text{ m}Since square M has same perimeter, and perimeter of square P = 4 \times side,Side of square M = \frac{40}{4} = 10 \text{ m} 7. Which among A, B, and C has the greatest perimeter? Given dimensions for shapes A, B, and C: - Shape A sides: 3 cm, 5 cm, 4 cm, 4 cm, 3 cm, 3 cmSum = 3 + 5 + 4 + 4 + 3 + 3 = 22 cm- Shape B sides: 5 cm, 5 cm, 4 cm, 4 cm, 3 cm, 3 cmSum = 5 + 5 + 4 + 4 + 3 + 3 = 24 cm- Shape C sides: 4 cm, 3 cm, 5 cm, 3 cmSum = 4 + 3 + 5 + 3 = 15 cm Shape B has the greatest perimeter: 24 cm