what in solve 2x²=16

x = 2√2We're asked to solve the following:[tex]\sf 2x^2=16[/tex]Begin by dividing both sides by 2.[tex]\sf x^2=8[/tex]Take the square root.[tex]\sf x=\sqrt8[/tex]Rewrite.[tex]\sf x=\sqrt{4*2}[/tex][tex]\sf x=\sqrt{4}*\sqrt{2}[/tex]We know the square root of 4, it's 2.Rewrite:[tex]\sf x=2\sqrt{2}[/tex]

Answered by Eloquence | 2025-07-03

Start with the equation:  2x² = 16Divide both sides by 2:  x² = 8Take the square root of both sides:  x = ±√8Simplify the square root:  x = ±2√2 (exact form)  or  x ≈ ±2.83 (rounded decimal)If you are solving over real numbers, both x = 2√2 and x = -2√2 are correct.If you meant 2x = 16 (not x²), then the answer would be x = 8.

Answered by ulancheskadana | 2025-07-03