Activity #2 C. Find the first three terms of the given general term. 1. an = -4+n 2. an = 6n+1 n+1 3. an = 4. an = = n-4 n² n+1 2n² 5. ann³ An
Answer (2)
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Answer:Step-by-step explanation:The first three terms for each sequence are: \(a_{n}=4n\implies \{4,8,12\}\); \(a_{n}=6n-1\implies \{5,11,17\}\); \(a_{n}=\frac{n}{n+1}\implies \{\frac{1}{2},\frac{2}{3},\frac{3}{4}\}\); \(a_{n}=\frac{n^{2}}{2n^{2}-1}\implies \{1,\frac{4}{7},\frac{9}{17}\}\); \(a_{n}=n^{3}\implies \{1,8,27\}\).
