find the 25th term of the arithmitic sequence 3,7,11,15,19
Answer (1)
Answer:99Step-by-step explanation:{ 3, 7, 11, 15, 19,... 99 } Formula:an = a1 + (n-1) dan = missing terma1 = first term n = number of elements d = common difference Solution:a25 = 3 + (25 - 1) 4a25 = 3 + (24) 4a25 = 3 + 96a25 = 99
