N=1,2,31.(n-2)²2.(3+1/n)^n​

Answer:Let's solve each expression for n = 1, 2, and 3. 1. (n - 2)² - n = 1: (1 - 2)² = (-1)² = 1- n = 2: (2 - 2)² = 0² = 0- n = 3: (3 - 2)² = 1² = 1 2. (3 + 1/n)^n - n = 1: (3 + 1/1)^1 = 4¹ = 4- n = 2: (3 + 1/2)² = (3.5)² = 12.25- n = 3: (3 + 1/3)³ = (3.333...)³ ≈ 37.037 Therefore: For (n-2)²: 1, 0, 1 For (3 + 1/n)^n: 4, 12.25, ≈ 37.037

Answered by joanmangao05 | 2025-07-01