f(x)=3x²-x+5 a.f(x-1) b.f(3)+(-3) c.f(1) f(1) solve that using the evaluating function
Answer (1)
a.f(x - 1) = 3(x - 1)² - (x - 1) + 5= 3(x² - 2x + 1) - x + 1 + 5= 3x² - 6x + 3 - x + 1 + 5= 3x² - 7x + 9b.f(3) = 3(3)² - 3 + 5 = 27 - 3 + 5 = 29f(3) + (-3) = 26c.f(1) = 3(1)² - 1 + 5 = 3 - 1 + 5 = 7
