x = ±3√5We're asked to solve the following equation:[tex]\sf 5x^2=225[/tex]Divide both sides by 5:[tex]\sf x^2=45[/tex]Take the square root:[tex]\sf x=\pm \sqrt{45}[/tex]Simplify:[tex]\sf x=\pm\sqrt{5*9}[/tex]Rewrite:[tex]\sf x=\pm 3\sqrt5[/tex]
Answer:5x²=255 divide both side by 5x²=51then take the square root of 51and solve the x²x² divide the 2 x squared just like I did2--- = 1 2then the square root of √51 x²=±√51x=±7.14 so the solution are x = 7.14 and x = -7.14