Answer:There are 5 computers, 3 of which are defective (D) and 2 are non-defective (N). The principal will get 2 computers.The possible combinations of computers the principal can get are:1. 2D (2 defective)2. 1D, 1N (1 defective, 1 non-defective)3. 2N (2 non-defective)Let's find the values of the random variable T (number of defective computers):1. T = 2 (2 defective computers)2. T = 1 (1 defective computer)3. T = 0 (0 defective computers)So, the values of the random variable T are 0, 1, and 2.