a man of 65 kg stands on a solid floating on water. If the solid has a density of 0.6 g/cm3 and the man standing on it is just barely out of the surface of the water, determine the volume of the solid
Answer (1)
The volume of the solid ice the man is standing on is 108,333.33 cm³.Man’s mass (m) = 65 kg = 65,000 gDensity of solid = 0.6 g/cm³At equilibrium: weight of man = buoyant force = weight of displaced waterWater’s density = 1 g/cm³Buoyant force = volume displaced × densitywater65,000 g = V × 1 g/cm³ V = 65,000 cm³Now, volume of the solid (Vsolid) = mass / density Vsolid = (mass of man) / (densitysolid) Vsolid = 65,000 g / 0.6 g/cm³ = 108,333.33 cm³
