The data from the statement above are as followsT = 25°C = 298 KP = 600 kPa = 600,000 PaR = 117 N·m/kg·KDensity[tex]p = \frac{P}{RT} \\p = \frac{600000}{(117)(298)}\\ p = \frac{600000}{34866} \\p = 17.21[/tex]The density is 17.21 kg/m³.Specific Weightγ = ρ × gγ = 17.21 × 9,81γ = 168.88 N/m³The specific weight is 168.88 N/m³.Specific Volume[tex]v = \frac{1}{p}\\v = \frac{1}{17.21}\\ v = 0.0581[/tex]The specific volume is 0.0581 m³/kg.