If the volumetric expansion coefficient of alcohol is \( 2 \times 10^{-3} \, \text{°C}^{-1} \), and the temperature difference is \( 50 \, \text{°C} \), what is the ratio of the final expanded volume to the original volume
Answer (1)
The formula volume expansion is: [tex]Vf = V0 (1 +\beta[/tex]Δ[tex]T)[/tex]Where: [tex]V0 =[/tex] original volume[tex]\beta = 2[/tex] x [tex]10^{-3}[/tex]Δ[tex]T = 50[/tex][tex]Ratio =[/tex] [tex]\dfrac{Vf}{V0} = 1 + \beta[/tex]Δ[tex]T = 1 + (2[/tex] x [tex]10^{-3} ) (50) = 1 + 0.1 = 1.1[/tex]Final answer: The final volume is 1.1 times the original volume
