2Al2O3 --> 4Al + 3O2
The experiment was performed and 12.5g of oxygen was actually obtained. What is the percent yield for the reaction?
Answer (1)
To calculate the percent yield, we need to follow these steps:Determine the theoretical yield of oxygen (O₂) based on the given amount of aluminum oxide (Al₂O₃).Use the actual yield, which is given as 12.5g of oxygen.Calculate the percent yield using the formula:Percent Yield = (Actual Yield / Theoretical Yield) × 100%Step 1: Calculate the theoretical yieldFrom the balanced chemical equation:2Al₂O₃ → 4Al + 3O₂This shows that 2 moles of Al₂O₃ produce 3 moles of O₂.Now, let's calculate the molar mass of Al₂O₃ and O₂:Molar mass of Al₂O₃ = (2 × 26.98) + (3 × 16.00) = 101.96 g/molMolar mass of O₂ = 2 × 16.00 = 32.00 g/molWe are given 12.5g of oxygen, so we can now calculate how many moles of oxygen this corresponds to:Moles of O₂ = 12.5g ÷ 32.00 g/mol = 0.3906 mol of O₂Now, let's use stoichiometry to find the theoretical amount of O₂ produced. From the equation, 2 moles of Al₂O₃ produce 3 moles of O₂.Thus, the moles of O₂ that can be produced from 1 mole of Al₂O₃ is:Moles of O₂ = (3/2) × moles of Al₂O₃Step 2: Calculate percent yieldOnce you've done the calculations, you can plug in the actual yield and theoretical yield into the formula.
